How to choose the right heat pump dryer? No matter what kind of material is dried, the first choice is to figure out the moisture ratio and moisture content of the dried items. A simple test of a few catties of fresh goods can dry one catty of dry goods.

Second: Confirm the dehydration characteristics of the materials. Generally, the dehydration of fruits and vegetables is faster; the dehydration of the materials that are dried as a whole is slower, especially the materials with shells or similar to peppers with a layer of film.

Third: After determining the moisture content and dehydration characteristics of the material, you can confirm how much material needs to be processed in a single time.

Assuming that a single baking of 2000 kg of fresh goods requires dehydration of 500 kg and drying within 10 hours.

500÷10=50kg/h, which gives 50kg dehumidification per hour;

Then when selecting the heat pump host, you need to follow up this data as a reference. Whether the host can evaporate 50kg of water per hour for this material and whether it can discharge moisture in time, if a closed-loop dehumidification heat pump is used, can the dehumidification capacity be achieved, even if the dehumidification capacity is reached Whether the temperature can be maintained continuously and other factors, as the drying equipment of various manufacturers are different, it is necessary to understand the parameters and performance of the dryer.

Choose an open drying heat pump or a closed drying heat pump?

The easiest way is to look at the moisture. The material with the larger moisture content should choose a closed-loop dehumidification and drying heat pump. The materials with relatively low moisture content and longer drying time or with a shell on the outside are better to choose an open-loop heat pump for drying. Dry unit.

After the drying equipment is determined, the size of the drying room is determined. We generally first determine how much material can be placed in 1 square. The thickness of different materials is different. For example, walnuts can be thicker, and sliced fruits and vegetables are not allowed. It is too thick to avoid stacking. Determine how many kilograms can be placed per square, and then calculate the number of layers of the drying rack and the area of a single layer.

For example: 4,000 kg of walnuts need to be dried, 1 square to stack 2 layers of walnuts can hold 20 kgs, 200 squares can hold 4000 kgs, assuming the baking pan is 1mX1m and the depth is 5cm, then 200 such plates are needed. If the drying car sits on the 20th floor without a car, only 10 drying cars can be placed.

After confirming the size of the drying pan and the drying car, the optimal size and size of the drying room can be designed according to the area of the 10 drying cars, the area of the equipment installation, and the area of the air supply structure.

Matters needing attention: please pay attention to the dehydration characteristics of items and the stacking thickness of materials

Everyone: Do not compare the original coal drying method with the heat pump drying capacity.